Election in Arkansas
1884 United States presidential election in Arkansas
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| |  |  | | Nominee | Grover Cleveland | James G. Blaine | | | Party | Democratic | Republican | | Home state | New York | Maine | | Running mate | Thomas A. Hendricks | John A. Logan | | Electoral vote | 7 | 0 | | Popular vote | 72,734 | 51,198 | | Percentage | 57.83% | 40.70% | |
 County Results | Cleveland 40-50% 50-60% 60-70% 70-80% 80-90% 90-100% | Blaine 50-60% 60-70% 70-80% 80-90% 90-100% | |
President before election
Chester A. Arthur
Republican | Elected President
Grover Cleveland
Democratic | |
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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| Mayoral elections |
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- 1996
- 2000
- 2004
- 2008
- 2012
- 2016
- 2020
- 2024
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The 1884 United States presidential election in Arkansas took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. Arkansas voters chose seven electors to the Electoral College, which selected the president and vice president.
Arkansas voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 17.12%.
Results
See also
References
- ^ "1884 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved November 25, 2020.
