1880 United States presidential election in Alabama
Election in Alabama
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| Turnout | 12.03% of the total population  5.19 pp[1] | |||||||||||||||||||||||||
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 County results
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The 1880 United States presidential election in Alabama took place on November 2, 1880, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Alabama was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 59.99% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee, Chester A. Arthur, with 37.10% of the vote.[2]
Results
| 1880 United States presidential election in Alabama[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 91,130 | 59.99% | 10 | 100.00% | ||
| Republican | James A. Garfield of Ohio | Chester A. Arthur of New York | 56,350 | 37.10% | 0 | 0.00% | ||
| Greenback | James B. Weaver of Iowa | Barzillai J. Chambers of Texas | 4,422 | 2.91% | 0 | 0.00% | ||
| Total | 151,902 | 100.00% | 10 | 100.00% | ||||
See also
References
- ^ "1884 Presidential Election Results Alabama Total Population Turnout".
- ^ a b c "1880 Presidential Election Results Alabama".
State and district results of the 1880 United States presidential election | ||
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